The joint density of W and Z will be uniform on this region Let A denote the interior of the parallelogram Since it has area 1, we conclude fW;Z(w;z) = 1((w;z) 2 A) Note that we avoided computing the Jacobian Now we can gure out what fXjZ(xjz) is We must consider two cases First suppose 0 z 1 Given Z = z, X is uniformly distributedTable of Contents 01 High diversification, our key strength to face very different realities T LATAM T EUROPE 485% revenues;¦ u r k g t z y z w g r b t ½ x § g z r g w b 1dxgrmlpr lqvwuxnflmd /lhwr #dqdv lqvwuxnflmd v g y x y i u n g w g q z i g p l *heuxlnvddqzlmlqj %uxnvdqylvqlqj ,qvwuxnfmd rev xjl 0dqxdo gh lqvwux©·hv 8,7 /7 /9 0 1/ 12 3/ 37 0dqxdo gh xwlolduh / t x y w z q o f v u d q x v r z g y g o o 1£yrg qd srx @¯ydqlh Guide Leaflet J G T 3 Sx Cj 7 2 O Gt J I Cj V T x[V[g 'w¶ "¯^ Z'¥